Descriptive Programming with Variables on the Data Table
Question ID: 104135

I’m trying to use descriptive programming and a parameter from the local data table to click on a link. The descriptive I’m using is outertext and the outertext is stored as a parameter on the Local Data Table. This is what I have:


What I want to do is use DataTable("Category", dtLocalSheet) in place of outerTextInfo but I can’t seem to get the proper syntax. How should this be coded?

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Posted by (Questions: 2, Answers: 3)
Asked on June 17, 2010 2:45 pm
Answers (3)
Private answer

Set a variable for DataTable(''Category'', dtLocalSheet)
Category=DataTable(''Category'', dtLocalSheet)

Next, use that variable as the ''outertext.''

Make sure the variable is concatenated onto ''outertext:'' and is NOT within the quotation marks (''''). This way, the Link will use the varable Category instead of looking for ''outertext:=Category''. Make sense?

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Posted by (Questions: 1, Answers: 1)
Answered on June 17, 2010 6:34 pm
Private answer

Petri basically had the correct format, except that you need to use the := between the property and the property value. If you are using a variable, you do have to make sure that the variable is not inside of the quotes like Petri mentioned, because it will be interpreted as a literal value instead of a variable. No matter what property or property value combination you use, the pattern of := is always the same (also there are not spaces between the property, the := and the value). If you find that QTP does not recognize the object with a single property/value combination, you can use multiple sets, just make sure they are separated by commas outside of the pair. Try this modified code from the above examples:

outerTextInfo = DataTable(''Category'', dtLocalSheet)
Browser(''title:=Browser'').Page(''title:=Page'').Link(''outertext:='' & outerTextInfo).Click

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Posted by (Questions: 2, Answers: 477)
Answered on June 28, 2010 2:10 pm
Private answer

Try this:

Browser(''micClass:=Browser'').Page(''micClass:=Page'').Link(''name:=BlahBlah'').Select DataTable.value(''Category'',dtGlobalSheet)

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Posted by (Questions: 2, Answers: 1)
Answered on June 17, 2010 3:01 pm

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